Mineral Wool thickness needed to match ThermaCote performance at 1mm

Thermal Conductivity of Rockwool Products:-

1. ThermalRock S Series:
   • S40 (Density: 40 kg/m³): λ = 0.037 W/m·K​
   • S50 (Density: 50 kg/m³): λ = 0.036 W/m·K​
   • S60 to S100 (Densities: 60-100 kg/m³): λ = 0.036 W/m·K​
2. Thermal Insulation Roll:
   • Density: Not specified​
   • Thermal Conductivity: λ = 0.044 W/m·K source ​rockwool.com

Calculating Required Thickness to Match ThermaCote’s R-Value:

ThermaCote achieves an R-value of 1.87 m²·K/W at a 1mm thickness. To determine the necessary thickness of Rockwool to match this R-value, we use the formula:​

Thickness=R×λ

Applying this:

1. For ThermalRock S50 (λ = 0.036 W/m·K):

   Thickness=1.87m².K/W×0.036W/m.K=0.06732m=67.32mm

2. For Thermal Insulation Roll (λ = 0.044 W/m·K):
   Thickness=1.87m².K/W×0.044W/m.K=0.08228m=82.28mm

Conclusion:

The required thickness of Rockwool to match ThermaCote’s R-value of 1.87 m²·K/W varies based on the specific product:

• ThermalRock S50: Approximately 67.32 mm​
• Thermal Insulation Roll: Approximately 82.28 mm​

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