PIR boards, typically have thermal conductivities ranging from 0.022 W/m·K to 0.026 W/m·K, depending on factors such as facings and manufacturing processes.
Impact on Required Thickness
The required thickness to achieve a specific R-value depends on the thermal conductivity (λ) of the insulation material. Using the formula:
Thickness=R×λ
Applying this:
For λ = 0.022 W/m·K:
Thickness=1.87m2⋅K/W×0.022W/m⋅K =0.04114m=41.14mm
For λ = 0.024 W/m·K:
Thickness=1.87m2⋅K/W×0.024W/m⋅K =0.04488m=44.88mm
For λ = 0.026 W/m·K:
Thickness=1.87m2⋅K/W×0.026W/m⋅K =0.04862m=48.62mm
Conclusion
The required thickness of a PIR board to match ThermaCote’s R-value of 1.87 m²·K/W varies between 41.14mm and 48.62mm, depending on the board’s specific thermal conductivity.
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